Steve is analyzing two linear functions, f(x) and g(x). Will they intersect? f(x) graph of the function f of x equals x plus 1. This is the table: g(x) x g(x) 1 1 2 3 3 5 Answer choices: (a)Yes, at a point with a positive x-coordinate (b)Yes, at a point with a negative x-coordinate (c)Yes, at a point where x is zero (d)No, they will not intersect
Try to plot these functions.
im confused...
@geerky42
Can you graph the line f(x) = x+1 ?
I dont know how
Think of f(x) as y. Does this help?
not really. I'm just so confused
f(x)=x+1 if x = 0 what will f(x) equal
f(0)?
f(x) =0 So if x=1 what will f(x) =?
f(x)=1?
I have attached a graph for you to use. Think of y as f(x). So we say x = 0 then f(x) = 1. Can you plot that point on the graph?
yes it'd be (0,1) correct?
Let's try that again. If x=1 and f(x) = x+1 What will f(x) be?
Yes(0,1) is correct. Now what will be the points when x=1?
(1,1) correct?
No that is incorrect. Look at the function. It says f(x) (which means the value of the function for(x) equals x+1. So if x=1. And our function is x+1..What will f(x) be>
f(x) would be 2? Right?
Correct so our coordinates for the value of x will be what on the graph?
(1,2) correct?
Correct..Now plot points for x=-2 and for x=4. What will the coordinates be?
am i still using x+1=f(x)? That just confused me...
(-2,2) is that correct?
You are still using f(x) = x+1
So if x= -2 what is F(x)
f(x)=-1 correct?
|dw:1403922342570:dw|
Yes
I attached something they may make it easier to understand. But now that you have the coordinates you need to plot them on the graph and draw your line
so they would be (-2,-1) (-1,0) (0,1) (1,2) and (2,3)
Very good...did you graph the line?
yes. on a sheet of paper.
|dw:1403922981494:dw| Something like this?
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yes lol disregard that ^^^^
The second line iw easy as they give you x and g(x). All you need to do is plot them and see where they intersect with the line you just drew.
they intersect when i plot (2,3) with (2,3) correct?
Terrific...So which is the correct answer.
a?
Winner..winner chicken dinner..good job....
Thank you SOOOOOO much!!!!
Your more than welcome
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