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How do I convert f(x)=x^2-4 to vertex form?
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hmm its already in vertex form
middle term is 0 --> (x-0)^2 -4 vertex at (0,-4)
Ohh, Alright! Thanks
But then is it already in standard form also?
yes it is....i guess technically you would write it as (x-0)^2 for vertex form though its not needed
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