What is the 1/5x+1/3y=4/5 and 1/5x+2y=54/5 if using the method of substitution?
isolate 1/5x value from the first equation, substitute it in the second equation
How do I do that?
Your first equation : 1/5x+1/3y=4/5 subtract 1/3y both sides, what do you get ?
1/5x = 1/2?
careful, you cannot subtract apples and coconuts
substitute this value in second equation and solve y
1/5x + 2(5-1/3y)=54/5
noo, you need to substitute it for 1/5x
combine the y's?
you need to get the common denominator to combine fractions
this is not looking right: 3/3y = 54
yeah we made a mistake, lets work it again
1/5x+1/3y=4/5 subtract 1/3y both sides : 1/5x = 4/5 - 1/3y substitute this value in second equation : 4/5 - 1/3y +2y=54/5 multiply through by 15 : 12 - 5y + 30y = 162 25y = 150 y = 6
substitute the y value in any one of the given equations and solve x
x=-.59
that doesn't look correct... check your work once...
1/5x+1/3y=4/5 plugin y = 6 1/5x + 1/3(6) = 4/5 1/5x + 2 = 4/5 multiply through by 5 : x + 10 = 4 x = ?
-6
(-6,6)
Looks good !
thank you!!!
Join our real-time social learning platform and learn together with your friends!