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How do you solve a dihibrid cross when parents are one of them (or both) heterocygous? I mean when both are homocygous is easy, for example MMBB x MMbb, F1 would be all MMBb ... but when we have Mmbbxmmbb or MmBbxmmbb ???
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|dw:1403999776932:dw| So you have to foil out what the parents have, once you foild it out you will get 4 different types of genotypes. for a dihybrid cross. Then you will put them into punnet square, and cross the 4 father with the 4 mother. |dw:1403999956062:dw| and then you would put both the father and mothers 2 alleles in the box, and I drew arrows because they were going to be the same outcome.
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