Mathematics
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OpenStudy (anonymous):
cos(x+pi/2) = -sin x
help! i need somebody.. help! not just anybody
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hartnn (hartnn):
Apply cos (A+B) formula
know what it is ?
hartnn (hartnn):
\(\cos(A+B) = \cos A\cos B - \sin A \sin B \)
hartnn (hartnn):
A = x
B =pi/2
OpenStudy (anonymous):
so,
cos x cos pi/2 - sin x sin pi/2
hartnn (hartnn):
yes
what are
cos pi/2 = ..
sin pi/2 = .. ?
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OpenStudy (anonymous):
do they equal each other?
hartnn (hartnn):
no...
cos pi/2 = 0
sin pi/2 = 1
do you have unit circle with you ?
OpenStudy (anonymous):
yes
hartnn (hartnn):
then look for pi/2 angle in it.
what are the co-ordinates when angle is pi/2 radians or 90 degrees
OpenStudy (anonymous):
(0,1)
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hartnn (hartnn):
correct,
those are read as
\((\cos \theta , \sin \theta)\)
and since \(\theta = \pi/2 \)
we get
\((\cos \pi/2 , \sin \pi/2 )=(0,1)\)
hartnn (hartnn):
thats why
cos pi/2 = 0
and sin pi/2 = 1
now plug these in your equation
OpenStudy (anonymous):
cos x 0 - sin x 1 ?
hartnn (hartnn):
correct!
simplify it
OpenStudy (anonymous):
- sin x
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hartnn (hartnn):
\(\huge \checkmark \)
OpenStudy (anonymous):
ahh! you're a life saver!
hartnn (hartnn):
^_^
OpenStudy (anonymous):
thank you sososososososososososo much!
hartnn (hartnn):
welcome sososososososososososo much!
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OpenStudy (anonymous):
:)