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Algebra
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|2x-1|-|1/3x+2|=3 with x>1/2
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What's your plan? Do you know that |x| = x when x is positive?
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Yes i know but how it do
What is the nature of (2x-1) when we KNOW that x > 1/2? Is it EVER negative?
Ok...i know but it is all threads
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?? Nonresponsive. 2x-1 > 0 2x > 1 x > 1/2 (1/3)x+2 > 0 (1/3)x > -2 x > -6 So, for x > 1/2, BOTH absolute value expressions are strictly positive. The absolute values can be simply discarded. Solve this: (2x-1)-((1/3)x+2)=3
Ok thank you
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