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Chemistry 14 Online
OpenStudy (superhelp101):

Which of the following quantum number combinations is not allowed in a ground-state atom? (7, 4, -2, -½) (2, 1, 1, -½) (3, 2, 3, +½) (3, 0, 0, +½)

OpenStudy (superhelp101):

@Abhisar i don't know how to do this

OpenStudy (abhisar):

u remember the trick to calculate \(\huge\ m_l\) i taught u last time ?

OpenStudy (superhelp101):

a formula?

OpenStudy (abhisar):

yes

OpenStudy (superhelp101):

0 to (n-1)

OpenStudy (abhisar):

no that is for calculating l

OpenStudy (superhelp101):

oh oopps. idk:(

OpenStudy (abhisar):

ohkay...lets understand it once again

OpenStudy (abhisar):

this time pay attention..ok ?

OpenStudy (abhisar):

if u want i can give u answers straight away....but that will not be of much use

OpenStudy (superhelp101):

ok i was but I have so much to study I forget :/

OpenStudy (superhelp101):

can u just give me the formula

OpenStudy (abhisar):

yes i will, but actually there is no xact formula

OpenStudy (superhelp101):

ok

OpenStudy (abhisar):

First see thi http://prntscr.com/3xl1sw

OpenStudy (abhisar):

*this

OpenStudy (abhisar):

got it ?

OpenStudy (superhelp101):

yep haha thanks!

OpenStudy (abhisar):

wait !

OpenStudy (abhisar):

it's not over :D

OpenStudy (abhisar):

now u know which one is called what. U have to check now if the value given is correct or not ?

OpenStudy (abhisar):

getting something ?

OpenStudy (abhisar):

if n is given then, l ranges from 0 to n-1 now for each l, m\(_l\) ranges from -l to l

OpenStudy (superhelp101):

okay

OpenStudy (abhisar):

Now check \(\huge\ m_l\) given in the third option. it is incorrect !

OpenStudy (superhelp101):

yeah it is

OpenStudy (abhisar):

So third option is the answer !

OpenStudy (superhelp101):

ok :) thanks you!

OpenStudy (abhisar):

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

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