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Calculus1 24 Online
OpenStudy (anonymous):

I'm stuck on taking the inverse of a function of f. f(x) = square root of x2 − 4 ,x ≥ 2. So far I'm at the step where I'm supposed to take the square root of each side and it's x^2+4=y^2. How do I take a square root of X^2+4 and then what is the final f^-1 (x)=____?, ≥0

OpenStudy (anonymous):

Where does the x≥ 2 go in the formula?

OpenStudy (precal):

that is the restriction given, otherwise the inverse function will not be a function

OpenStudy (anonymous):

Someone please help!

OpenStudy (neer2890):

\[f(x)=\sqrt{x ^{2}}-4??\]

OpenStudy (anonymous):

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