Which of the following is not = to 0
a. cos(pi/2)
b. tan(0)
c. cos(pi/4)-sin(pi/4)
d. sin^-1(pi)
e. cos^-1(1)
I know the answer is either d or e
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OpenStudy (anonymous):
sin pi is 0
cos 1 is (pi/2))
OpenStudy (dumbcow):
sorry that was not what they wanted...
cos(?) = 1
sin(?) = pi
OpenStudy (anonymous):
2pi
0
OpenStudy (dumbcow):
no sin(0) = 0
OpenStudy (dumbcow):
cos(0) = 1
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OpenStudy (dumbcow):
answer then must be D
OpenStudy (anonymous):
but it's inverse sin and inverse cos the inverse is confusing to me
OpenStudy (dumbcow):
ok the output of the inverse is the angle
\[\sin \theta = x \rightarrow \theta = \sin^{-1} x\]
so when they ask about an inverse, think sin of what angle will give me that number
example
\[\cos^{-1} \frac{\sqrt{2}}{2}\]
rewrite it as
\[\cos \theta = \frac{\sqrt{2}}{2}\]
then from the unit circle you know the angle must be pi/4
\[\cos^{-1} \frac{\sqrt{2}}{2} = \frac{\pi}{4}\]
OpenStudy (anonymous):
so because it's cos^-1(1) the angle is 0 therefore cos^-1(1)=0?
OpenStudy (dumbcow):
correct
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