Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Use synthetic division to divide the following problems. (x2 + 13x + 40) ÷ (x + 8)

OpenStudy (anonymous):

Please help!!!!!

OpenStudy (anonymous):

it is almost impossible to write division here start with the coefficients

OpenStudy (anonymous):

1 13 40

OpenStudy (anonymous):

then put a \(-8\) on the side 1 13 40 -8 ________________

OpenStudy (anonymous):

bring down the 1 1 13 40 -8 _______________ 1

OpenStudy (anonymous):

\(-8\times 1=-8\) 1 13 40 -8 -8 _______________ 1

OpenStudy (anonymous):

add 1 13 40 -8 -8 _______________ 1 5

OpenStudy (anonymous):

-8*5=-40 1 13 40 -8 -8 -40 _______________ 1 5

OpenStudy (anonymous):

add 1 13 40 -8 -8 -40 _______________ 1 5 0

OpenStudy (anonymous):

so there is no remainder and \[x^2+8x+40=(x+8)(x+5)\] which you probably could have figured out in ten seconds without division

OpenStudy (anonymous):

oops typo there i meant \[x^2+13x+40=(x+8)(x+5)\]

OpenStudy (anonymous):

thank you! would you be able to help me with one more? just to get me started because I think I got most of it. @satellite73

OpenStudy (anonymous):

k

OpenStudy (anonymous):

Let f(x) = 4x3 + 7x2 – 13x – 3 and g(x) = x + 3. Find f of x over g of x

OpenStudy (anonymous):

\[\frac{f(x)}{g(x)}=\frac{4x^3+7x^2-13x-3}{x+3}\] is a start now you can divide as before if you need to

OpenStudy (anonymous):

this time you will get a quotient and a remainder, since \(x+3\) does not divide evenly

OpenStudy (solomonzelman):

I totally agree with one of satelline's posts, why synthetic division when you can just factor ?

OpenStudy (anonymous):

wanna use synthetic division for this one?

OpenStudy (anonymous):

yes, please im supposed to for my assignment.

OpenStudy (anonymous):

same as before list the coefficients 4 7 -13 3 -3 ____________________

OpenStudy (anonymous):

bring down the 4 4 7 -13 3 -3 ____________________ 4

OpenStudy (anonymous):

muliply -3*4=-12 4 7 -13 3 -3 -12 ____________________ 4

OpenStudy (anonymous):

add 4 7 -13 3 -3 -12 ____________________ 4 -5

OpenStudy (anonymous):

-3*-5=20 4 7 -13 3 -3 -12 20 ____________________ 4 -5

OpenStudy (anonymous):

damn arithmetic mistake!

OpenStudy (anonymous):

-3*-5=15!! 4 7 -13 3 -3 -12 15 ____________________ 4 -5 2

OpenStudy (anonymous):

i see i made another mistake, the last number is \(-3\) not \(3\) so final answer is \[4x^2-5x-7-\frac{9}{x+3}\]

OpenStudy (anonymous):

wait you lost me. where did the 20 come from?

OpenStudy (anonymous):

that was a total mistake that is why i changed it to 15

OpenStudy (anonymous):

oh okay sorry

OpenStudy (anonymous):

there, just got rid of the mistake one and left the correct one up

OpenStudy (anonymous):

okay! again thank you so much!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!