Question

Find LCD for each list of rational expressions.


2x/3x^2 + 4X +1 , 7/2x^2 - x - 1

I solved 2x/3x^2 + 4X +1 all fine.
3x(x+1) + 1(x+1)
(3x+1)(x+1)

I get stuck on

7/2x^2 - x - 1

Answer 1

how can you say that
\[\frac{ 2x }{ 3x ^{2} }+4x+1=(3x+1)(x+1)\]

Answer 2

we are ignoring the numerator in this problem

Answer 3

I think it's \[\frac{ 2x }{ 3x ^{2}+4x+1 }\]

Answer 4

3x2+4x+1 = 3x^2 + 3x +x +1
3x(x+1) +1(x+1)
(3x+1)(x-1)

Answer 5

\[2x ^{2}-x-1\]
\[=2x ^{2}-2x+x-1\]
=2x(x-1)+1(x-1)
=(2x+1)(x-1)

Answer 6

see this is where i am confused

Answer 7

sorry! i ment
7/2x^2 - 2x - 1

Answer 8

for the original equation

Answer 9

wait

Answer 10

your right

Answer 11

i was reading problem wrong

Answer 12

\[\frac{ 7 }{ 2x ^{2}-x+1 }=\frac{ 7 }{ (2x+1)(x-1) }\]

Answer 13

I think you got it...!