medal and fan for help.....
go ahead
Which formula would be used to determine the surface area of this pencil? (Hint: This is a composite figure of two shapes)
The quantity 2 times pi times radius squared plus 2 times pi times radius times height, end quantity, plus the quantity pi times radius squared plus pi times radius slant height, end quantity minus two times quantity pi times radius squared, end quantity The quantity 2 times pi times radius squared plus 2 times pi times radius times height, end quantity, plus the quantity pi times radius squared plus pi times radius slant height The quantity pi times radius squared plus 2 times pi times radius times height , end quantity, plus the quantity 2 times pi times slant height The quantity 2 times pi times radius squared plus 2 times pi times radius times height, end quantity, minus the quantity pi times radius squared, end quantity, plus the quantity pi times radius squared plus 2 times pi times slant height, end quantity, minus the quantity pi times radius squared
those are the choices
I'm going to assume there should be a diagram along with this? :)
no it just like a pic of a cylinder and a cone to make a pencil
The surface area of a cylinder will be the \[\large \pi r^2 + 2\pi r h\] And the surface area of the cone would be the \[\large \pi rs\] where 's' is the slant height... so \[\large \pi r^2 + 2\pi rh + \pi rs\] Haha it looks like A, they tried to work it weird The quantity 2 times pi times radius squared plus 2 times pi times radius times height, end quantity, plus the quantity pi times radius squared plus pi times radius slant height, end quantity minus two times quantity pi times radius squared, end quantity \[\large 2\pi r^2 + 2\pi rh + \pi r^2 + \pi rs - 2\pi r^2\] \[\large 3\pi r^2 + 2\pi rh + \pi rs - 2\pi r^2\] \[\large \pi r^2 + 2\pi rh + \pi rs\] They match...so A would be correct here
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