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fund the limit, if it exists limx→9f(x), f(x)= [x+9 x<9] [27−x x≥9]
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@agent0smith
Usually i think you'd just plug in 0 for x but they arent equal, so does the limit not exist?
You definitely do not just plug in 0 for x. In this case, you plug in the value that x is approaching, and check the left hand limit equals the right hand limit. What value is x approaching?
oh, 9
So the limit is 18!! right?
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