Question

What is the equation of the line that passes through the points (1,2/3) and(-1,-1)?

Answer 1

I will give you the basic steps. Tell me if you need me to help you further.
First, find the slope between the two points.
\[m=\frac{ y _{2}-y_{1} }{ x_{2}-x_{1} }\]
Then, substitute the slope and one coordinate set of points into the slope-intercept form equation:
\[y=mx+b\]
Solve for b.
Once you have m and b, you should be good to go.
If you need it in standard form, I will assist you further if needed.

Answer 2

I got the slope as 1 and 1/5 is that correct?

Answer 3

One moment, I need to solve it myself.

Answer 4

Ok

Answer 5

How did you get 1 1/5 for the slope?

Answer 6

I plugged in the ys and the xs and then divided

Answer 7

Good try, but unfortunately it is incorrect.
Here is how to do it correctly:
\[m=\frac{ -1-2/3 }{-1-1 }=\frac{ -1 and 2/3 }{-2 }\]
-1 and 2/3 is simplified to -5/3 (mixed number to improper fraction)
Now we are left with\[\frac{ -5/3 }{ -2 }\]
We can divide them now. To divide fractions, we take the reciprocal of the second number, in this case -2 and make it 1/-2 (Whole numbers have a one as the denominator) then multiply.
\[\frac{ -5 }{ 3 }*\frac{ 1 }{ -2 }\]
After multiplying, we have -5/-6 or 5/6
m= 5/6

Now that we have this, can you do the second part?

Answer 8

B= -1/6

Answer 9

Correct. Good job. So, your equation is:
y=5/6x-1/6

Answer 10

Yes thanks

Answer 11

You're welcome.