Question

how does X^0=1?

Answer 1

using the law of exponents,
\[a^x * a^y =a^{x+y}\]
so
\[a^0*a^x=a^{0+x}=a^x\]
from which we can deduce that
\[a^0 = 1\]
by the identity law.

Answer 2

but where does the one come from?

Answer 3

@mathmate

Answer 4

From
\[a^0*a^x=a^x\]
divide both sides by a^x
\[a^0*a^x/a^x=a^x/a^x\]
=>
\[a^0=1\]

Answer 5

but wouldn't it be
a^0 / a^x * a^x = a^x/a^x
?

Answer 6

its the crazyness of math

Answer 7

acutally I would like a nonsarcastic remark
but what can you expect from an 8 year old?
yeah ur excused