equation: 2x + 3y = 1,200 Describe how you would graph this line using the slope-intercept method.
@jdoe0001
hmm
slope-intercept formula y = mx + b rearrange eqn in that format
when x = 0 what is y? when y = 0 what is x?
I don't get why you're replacing the x and y with 0?
the easiest values to use to get 2 of the points to graph when x = 0 y = 1200 so you have the point (0, 1200) when y = 0 find x this is another point on the line connect the points to get the line satisfying y= -2/3x + 1200
you can use any x values to calculate the corresponding y value and then get points on the line to graph
recall the 400 was the y-intercept, thus is where the line touches the y-axis, or INTERCEPTS it thus the point (0, 400)
if the slope is positive the graph goes UP from left to right if it's negative the graph goes DOWN from left to right lemme recorrect my correction darn =)
so y=(0,400) and x is ??????????? sorry im just confused on what is plotted on the x axis.
hold... on I got a few things mixed up
correction the intercept is 1200/3 = 400 the point is (0, 400)
@MonikaCristello do you have any questions about the method?
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