Question

The function f(x) = 15(2)x represents the growth of a frog population every year in a remote swamp. Elizabeth wants to manipulate the formula to an equivalent form that calculates every half-year, not every year. Which function is correct for Elizabeth's purposes?

f(x) = 15(2 to the one half power)2x

f(x) = 15(22)the x over 2 power

f(x) = fifteen halves(2)x

f(x) = 30(2)x

Answer 1

@Gabylovesyou lmao same name

Answer 2

15(_2^1/2)^2x
15(2^2)^x/2
15/2(2)^x
30(2)^x

Answer 3

@jim_thompson5910

Answer 4

15(2)^x=15(2,1/2)^2x

Answer 5

Why? @$w3G_Godd

Answer 6

Do you think you can help me on another problem?

Answer 7

ya ill try

Answer 8

Izzy's heartbeat rate was measured on an EKG machine. After conversion, the function produced could be modeled by a sine function, and the wave produced a maximum of 8, minimum of −2, and period of ð. Which of the following functions could represent Izzy's EKG read-out?

f(x) = 8 sin ðx − 2

f(x) = 5 sin ðx + 3

f(x) = 5 sin 2x + 3

f(x) = 2 sin 2x + ð

Answer 9

maximum of the A function is 8*1-2 = 6, so it can't be.
maximum of the D function is 2*1 +pi ~ 5, so it can't be either.
Both b and c are viable.
By definition of periodic function, if f(x) has period T, f(kx) has period T/k,
it means that the period of function b would be 2, and function c would be pi, which is the required answer.

Answer 10

So C would be the correct answer?

Answer 11

@$w3G_Godd