Question

Find all values of x in the interval [0, 2π) that solve cos^3x / sinx = cotx.

Answer 1

Any idea?

Answer 2

I know how solve the problem, I just need to know what the interval thing means

Answer 3

Show your work, please

Answer 4

http://prntscr.com/3y6d1t

Answer 5

Just need to know what the interval thing means

Answer 6

sinx can't be 0

Answer 7

Ok. What does the interval thing mean?

Answer 8

the solution is not right

Answer 9

I'm not looking for the answer

Answer 10

I want to know what the interval thing means

Answer 11

2kπ?

Answer 12

same as 2πn?

Answer 13

You're telling me a text book is wrong?

Answer 14

http://prntscr.com/3y6f6h

Answer 15

nothing is conflict. That is the same with my logic

Answer 16

ok

Answer 17

You still have me confused on the interval thing...

Answer 18

you get cos x =0 --> x = pi/2 and 3pi/2 . If you don't have that interval, then, the perfect solution is x = \(\dfrac {\pi}{2}+2\pi n\) or x = \(\dfrac {3\pi}{2}+2\pi n\)
However, your interval restricts the \(2\pi n\) part, then it is just \(\pi/2\) or \(3\pi/2\)