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Mathematics 20 Online
OpenStudy (anonymous):

Use the graph of y = f(x) to graph the given function g. g(x) = -2f(x)

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@AnswerMyQuestions

OpenStudy (anonymous):

I don't get the question...

OpenStudy (anonymous):

me either :(

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

i tagged them before but no response

OpenStudy (anonymous):

@Garadon_Shagan

OpenStudy (anonymous):

Doesn't that basically mean for every value of f(x), g(x) is stretched by a factor of -2 or some-such? I.e. the gradient is reversed and made twice as steep?

OpenStudy (anonymous):

And which one of the attachments is actually the graph you're given?

OpenStudy (anonymous):

i guess i have no clue i don"t understand any of this i have passed all of my courses and not my two last one are these (pre calculus ) and i am stuck

OpenStudy (anonymous):

There was no given graph it was just the question and the answers that i attached

OpenStudy (anonymous):

So are the attachments your attempts at the answer or are you told they are the answer?

OpenStudy (anonymous):

One of the graphs is the answer

OpenStudy (anonymous):

one of those are the answer it just gave me that question and those answer choices

OpenStudy (anonymous):

It must be the last one! Actually quite obvious to me now: the third one has the dotted line as a reflection of the solid line graph (meaning if the solid line had gradient m then the dotted line has gradient -m) but if you look you'll also see that the dotted line graph is stretched! It is easy to miss because of the middle section which is just as wide for some reason *scratches head* but the legs are about two times as long! So that must be the correct one

OpenStudy (anonymous):

Thank you so much @Garadon_Shagan you are a life saver :)

OpenStudy (anonymous):

Haha thanks! Can you please tell me how can I get my engagement score up though? They are very obscure about it!

OpenStudy (anonymous):

I think by asking questions maybe ?

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