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Mathematics 17 Online
OpenStudy (anonymous):

i need help on a bunch of questions for an assignment will someone plz help me with ALL of them

OpenStudy (anonymous):

Not sure if I can answer all of them, but I'm willing to give it a shot

OpenStudy (anonymous):

same here

OpenStudy (anonymous):

ok lets see

OpenStudy (anonymous):

Margo and Carrie are trying to go to Idaho for Dawn's wedding. The probability of finding a flight for less than $400 is 1/7. The probability of Carrie making enough money babysitting to pay for her flight is 3/5. The probability of the girls being able to take time off from work is 1/2. What is the probability that they will make it to their friend's wedding?

OpenStudy (anonymous):

I think you'd have to find a common denominator between all three probabilities to start

OpenStudy (anonymous):

i need this assignment done today i dont have time to work it out with 20 other question :(

OpenStudy (anonymous):

Ummm, I'm not sure how to answer the question, I keep getting things that are over 100% i.e. 19/14 and 1.357....

OpenStudy (anonymous):

i dont have those for awners

OpenStudy (anonymous):

What are the possible answers?

OpenStudy (anonymous):

um i got the next one is Mr. Crosson selects two students from his class to present their reports on Spain. He places the names of each student in a box and picks one at a time. The class has 8 boys and 10 girls. What is the probability that Mr. Crosson will pick two boys in a row if he does not put the first name back in the box? Round your answer to the nearest percent.

OpenStudy (anonymous):

next one

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