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Precalc: Find all polar coordinates of point P where P =(4,-pi/3)
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In that expression, what is r? what is (theta)?
i dont know, thats all im given
|dw:1404237883482:dw|
choices are (4, -pi/ 3 + 2nπ) or (-4, -pi/ 3 + (2n + 1)π) (4, -pi/ 3 + (2n + 1)π) or (-4, -pi/ 3 + 2nπ) (4, -pi/ 3 + 2nπ) or (4, pi/3 + (2n + 1)π) (4, -pi/ 3 + 2nπ) or (-4, -pi/ 3 + 2nπ)
|dw:1404237999657:dw|
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so, to get this guy again, we just +2npi, that's it
@Bebong so d?
Let see!! now consider a) the first part matches with our logic, right? now, the second one -4, -pi/3 |dw:1404238483303:dw|
(2n+1) pi = 2npi + pi now, go around 2npi, we back to the same pot, right? 1 more pi |dw:1404238575306:dw|
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