Question

Solving rational equations...need help with the concept, then I can do the individual questions myself.

Answer 1

(7/8) - (1/x) = (3/4). Solve for x.

Answer 2

I tried to get a common denominator of 8x, so I ended up with (7x/8x) - (8/8x) = (6x/8x). That became (7x - 8)/(8x) = (6x/8x), and then 56x^2 - 64x = 48x^2 became 8x^2 - 64x = 0.

Answer 3

move the 7/8 over
(−1/x)=(−7/8)+(6/8)=(−1/8)

Answer 4

That's not how you solve this kind of problem. Algebra II. Fractions aren't in my answers, either. Thanks though.

Answer 5

@linda3 Please help :)

Answer 6

7/8- 1/x - 3/4

multiply by 8

7 - 8/x - 6

1 - 8/x

make answer = 0

1 - 8/x = 0

-8/x = -1

8/x = 1

multiply by x

so this leaves you with x = 8 -_-

Answer 7

Okay...I just want a second opinion b/c that's not anything like how I was taught to solve a rational equation.

Answer 8

@Kainui @Nurali @mathstudent55 @Australopithecus

Answer 9

Sir/Ma'am, A Warm Welcome To Open Study.
Sir/Ma'am please show your Working for the question you have posted.

Answer 10

I already have.

Answer 11

It's the second comment on this post. I just multiplied the first fraction by x/x, the second by 8/8, and the third by 2x/2x. Then I cross multiplied to get the aforementioned equation, and I converted it into standard form.

Answer 12

@goformit100 Hello?

Answer 13

@amistre64 @kmeis002 Please help.

Answer 14

ok -_-

Answer 15

What?

Answer 16

You can multiple by 8x for a common denominator. This should cancel out the x in second term and you should be left with something like:

\[7x - 8 = 6x \]

Then you may collect terms and solve from there.

Answer 17

Okay $w3G, I guess you're right...Let's give it a try.

Answer 18

┻━┻ ︵ヽ(`Д´)ﾉ︵ ┻━┻ lul

Answer 19

(7/8) - (1/x) = (3/4)

multiply thru by 8x to clear the fractions

7x - 8 = (3/4)8x

7x - 8 = 6x

Answer 20

we could also notice that 3/4 = 6/8 and see that 7-1 = 6 if x=8 :)

Answer 21

Great, thanks guys!!!

Answer 22

@$w3G_Godd I have NO idea what that drawing is of.

Answer 23

its me flipping 2 tables [̲̅$̲̅(̲̅5̲̅)̲̅$̲̅] ヾ(⌐■_■)ノ♪