Question

I really need help with this question!! Please!!! Find four consecutive even integers, such that the product of the first and second integers minus 8 is equal to the product of the third and fourth integers

Answer 1

Sir/Ma'am, A Warm Welcome To Open Study.
Sir/Ma'am please show your Working for the question you have posted.

Answer 2

x,x+2,x+4,x+6
x(x+2)-8=(x+4)(x+6)

Does that look helpful? Can you do it now?

Answer 3

I already have that step I am not sure what my next step would be... The only difference is I made my variable "n". Can you please help me a little further. I would really appreciate it.

Answer 4

Open up the brackets and solve the quadratic for x.

Answer 5

okay i got
n^2+2n-8=n^2+6n+4n+24
n^2+2n-8=n^2+10n+24
-8n-32=0
-8(n+4)=0
n=-4

Therefore n=-4
n+2=> -4+2=-2
n+4=> -4+4=0
n+6=> -4+6=2
is this correct??

Answer 6

▬Sir/Ma'am, A Warm Welcome To Open Study. Sir/Ma'am please show your Working for the question you have posted.▬

Answer 7

Yes it is correct :)

Answer 8

Thank you!! :D