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OpenStudy (anonymous):
PLEASE HELP!!! WILL GIVE MEDAL! The height of an arrow that is shot upward at an initial velocity of 40 meters per second can be modeled by h=40t-5t^2, where h is the height in meters and t is the time in seconds. Find the time it takes for the arrow to reach the ground.
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OpenStudy (yanasidlinskiy):
Hello, Kasie! Basically solve 0 = 40t - 5t^2 I will flip it around 5t^2 - 40t = 0 notice you can factor a t on the left side t(5t - 40) = 0 Can you proceed from there?
OpenStudy (anonymous):
Yes, thankyou @YanaSidlinskiy!
OpenStudy (yanasidlinskiy):
No problem!!:D Glad I could assist you!!:D
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