Can someone help please? I'll give a medal...

Which of the following shows the correct steps to find the value of 27^ (1/3)?

27^(1/3) = (9^3)^(1/3) = (9)^3(1/3) = 9
27^(1/3) = (3^9)^(1/3) = (3)^9(1/3) = 3
27^(1/3) = (3^4)^(1/2) = (3)^4(1/2) = 9
27^(1/3) = (3^3)^(1/3) = (3)^3((1/3) = 3

Question

Can someone help please? I'll give a medal...

Which of the following shows the correct steps to find the value of  27^ (1/3)?
 	
	 27^(1/3) = (9^3)^(1/3) = (9)^3(1/3) = 9
	 27^(1/3) = (3^9)^(1/3) = (3)^9(1/3) = 3
	 27^(1/3) = (3^4)^(1/2) = (3)^4(1/2) = 9
	 27^(1/3) = (3^3)^(1/3) = (3)^3((1/3) = 3

mrnood · Answer

the second column of all the  answers is trying to rearrange the initial expression

27^1/3

So looking at the first brackets in the second column you have
9^3, 3^9, 3^4 & 3^3 
Which of those is a correct substitution for 27?

anonymous · Answer

3^3

mrnood · Answer

Correct

anonymous · Answer

So, would it be the last one then?

mrnood · Answer

check it.

n^1/3 is another way of writing cuberoot(n)

so IS 27^1/3 = 3?