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Choose the point-slope form of the equation below that represents the line that passes through the point (-1, 6) and has a slope of -3.
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\(\bf \begin{array}{lllll} &x_1&y_1\\ &({\color{red}{ -1}}\quad ,&{\color{blue}{ 6}})\quad \end{array} \\\quad \\ slope = {\color{green}{ m}}= -3 \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\)
y - 6 = -3x - 3 y - 6 = -3(x + 1) y = -3x + 3 3x + y = 3
y-6=m(x-(-1)
yeap, recall that the slope = m = -3
thus y-6 = -3(x-(-1) y -6 = -3(x+1)
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ok whats next
oh nevermind lol
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