Question

PLEASE HELP - Will give medal!
(2x^2+3x-5)+(x^2+11x-7)=180
what is the value of x?

Answer 1

Solve for x over the real numbers:
3 x^2+14 x-12 = 180
Write the quadratic equation in standard form.
Divide both sides by 3:
x^2+(14 x)/3-4 = 60
Solve the quadratic equation by completing the square.
Add 4 to both sides:
x^2+(14 x)/3 = 64
Take one half of the coefficient of x and square it, then add it to both sides.
Add 49/9 to both sides:
x^2+(14 x)/3+49/9 = 625/9
Factor the left hand side.
Write the left hand side as a square:
(x+7/3)^2 = 625/9
Eliminate the exponent on the left hand side.
Take the square root of both sides:
x+7/3 = 25/3 or x+7/3 = -25/3
Look at the first equation: Solve for x.
Subtract 7/3 from both sides:
x = 6 or x+7/3 = -25/3
Look at the second equation: Solve for x.
Subtract 7/3 from both sides:
Answer: |
| x = 6 or x = -32/3

Answer 2

Thanks @DangerousJesse!