Need help with definite integrals
I find these confusing because I have to find the definite integrals for \[f \prime(x) dx\]
sorry I had to attach a file but you need to look at the graph
I need someone to double check my solutions 33. is 3 34 is 4 but I am not sure on this one 35 is 8/3
I found the slope of each line segment and then I calculate the dx of line segment
Can someone double check my solutions?
slope from (-4,-3) to (-1,-2) is 1/3 slope from (-1,-2) to (1,2) is 2 slope from (1, 2) to (3,-2) is -2
33 and 34 are correct 35 is wrong
an easier way is to use the fundamental theorem of calculus : \(\int_a^b f'(x) = f(b) - f(a)\)
for 33 : \(\int_{-4}^0 f'(x) = f(0) - f(-4) = 0 - (-3) = 3\)
for 34 : \(\int_{-1}^1 f'(x) = f(1) - f(-1) = 2 - (-2) = 4\)
I still got 8/3 using FTC
for 35
f(2) = 0 f(-3) = -8/3 0-(8/3) =8/3
oh yes ! i made a mistake you're right !
No problem. Thank you, I would not have thought to use FTC in the first place
good to know both ways :)
yes I agree
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