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find the domain of the composite function f o g f(x)=3/x-10 g(x)=sqrt(x-3)
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first off you need the domain of \(g\) you got that?
if not let me know i am just asking
yes
ok then you have \[f\circ g(x)=\frac{3}{\sqrt{x-3}-10}\]
you already know that \(x\geq 3\) for sure now you have to make sure that you are not dividing by zero, solve \[\sqrt{x-3}-10=0\] for \(x\) to get another restriction
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x-5, x+2
you lost me there
\[\sqrt{x-3}=10\\ x-3=100\\ x=103\] is what i get
how 10 become 100
i squared both sides
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