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Mathematics 19 Online
OpenStudy (anonymous):

Need help with pre-cal expansion. Look in comments for equation.

OpenStudy (anonymous):

Expand \[\sum_{k=1}^{4}(k-1)(k-2)\]

OpenStudy (anonymous):

I got (1-1)(1-2) +(2-1)(2-2) + (3-1)(3-2) +(4-1)(4-2). Is this right?

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

How about this one: Write 1, 4, 9, 16, 25, 36 in sigma notation.

OpenStudy (anonymous):

Is it \[\sum_{k=1}^{7}k^2\]

OpenStudy (azureilai):

That's what I got. But I am not sure about the 7. I had\[\sum_{k=1}^{6}k^2\] But I may be wrong. The second part is correct though

OpenStudy (anonymous):

Yeah, it's 6. Counted wrong.

OpenStudy (anonymous):

Okay, next is find the sigma notation for -3, -2, -1, 0, 1.

OpenStudy (anonymous):

Is it \[\sum_{k=-4}^{5}k+1\]

OpenStudy (azureilai):

The top number is 0 since you started at -4

OpenStudy (anonymous):

Ah, makes sense

OpenStudy (anonymous):

So \[\sum_{k=-4}^{0}k+1\]

OpenStudy (azureilai):

yep

OpenStudy (anonymous):

Awesome, thanks

OpenStudy (azureilai):

np

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