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If a = 1111..........1 (55 times) , b= 1+10 + 10^2 + 10^3 +10^4 and c=1 +10^5 +10^10 +...........+10^50 , then prove that (i) "a" is a composite number (ii) a=bc
Multinomials?
Nope, I am actually learning Sequences and series
@primeralph
@Miracrown
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@Hero
Use the formula for the sum of a a geometric series to find b and c first. b = ? c = ?
Okay after that
which one u need part b?
both
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11111 = b= 1+10 + 10^2 + 10^3 +10^4 .....100010001= c=1 +10^5 +10^10 +...........+10^50 soo... if u look at long multiplication now
you will see that due to that shift by a decimal place u musth ave all 1s
How to prove (i) then
|dw:1404282810008:dw|
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