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Mathematics 15 Online
OpenStudy (anonymous):

Not quite getting this

OpenStudy (anonymous):

If a = 1111..........1 (55 times) , b= 1+10 + 10^2 + 10^3 +10^4 and c=1 +10^5 +10^10 +...........+10^50 , then prove that (i) "a" is a composite number (ii) a=bc

OpenStudy (primeralph):

Multinomials?

OpenStudy (anonymous):

Nope, I am actually learning Sequences and series

OpenStudy (anonymous):

@primeralph

OpenStudy (anonymous):

@Miracrown

OpenStudy (anonymous):

@Hero

OpenStudy (mosaic):

Use the formula for the sum of a a geometric series to find b and c first. b = ? c = ?

OpenStudy (anonymous):

Okay after that

OpenStudy (dan815):

which one u need part b?

OpenStudy (anonymous):

both

OpenStudy (dan815):

11111 = b= 1+10 + 10^2 + 10^3 +10^4 .....100010001= c=1 +10^5 +10^10 +...........+10^50 soo... if u look at long multiplication now

OpenStudy (dan815):

you will see that due to that shift by a decimal place u musth ave all 1s

OpenStudy (anonymous):

How to prove (i) then

OpenStudy (dan815):

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