Question

When a wire is made smaller, the resistance increases. Which happens to the electric current?

Answer 1

Do you have options?
Ok, even if you don't.

\[R = \frac{\rho l}{A}\]
Now if \(l\) decreases, definitely \(R\) will also decrease. [Because they are proportional]

We know that, \(V = IR\) [From ohm's law]
Thus, \(R = \frac{V}{I}\)

And therefore, \[\frac{V}{I} = \frac{\rho l}{A}\]

When \(V, \rho,~~\& ~~A\) are kept constant.

I is inversely proportional to length and hence, when length decreases, electric current increases!

PS

I think you mean to say when wire length decreases, resistance decreases!