Question

x^2-y^2/x-y * 2xy/x^2+xy
someone help pleaseee.!

Answer 1

\[\frac{(x^2-y^2)(2xy)}{(x-y)(x^2+xy)}\]

There is an algebraic identity: \(x^2-y^2 = (x+y)(x-y)\)
From \(x^2+xy\) take '\(x\)' common, you'll have: \(x(x+y)\)


Writing it like that, we have:
\[\frac{(x+y)(x-y)(2xy)}{(x-y)(x+y)x}\]

Can you proceed now? :)

Answer 2

i got 2x2y • (x + y)2

Answer 3

How exactly?

If you see, \(x(x+y)(x-y)\) are all present in the numerator and in the denominator.
They cancel each other out don't they?

Look at it carefully, once more! :)