Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

A. y = four thirdsx + 8

B. y = four thirdsx + 3

C. y = -three fourthsx + 8

D. y = -three fourthsx + 3

@JoshR1213

Answer 1

@ganeshie8

Answer 2

Get the original equation into y=mx+b form first

Answer 3

4x-3y= -12

-3y= -12 -4x

y= 4 +4/3x

In other words, your new equation is y= 4/3x +b

So using y= 4/3x +b and the point (-3,4):

4= 4/3(-3/1) +B

4= -12/3 +b

4= -4 +b

b= 8

Therefore y= 4/3x +8

Answer 4

put in y=mx+b I always use this for equations like that