What is the equation of a line that passes through the point (3, -1) and is perpendicular to a line with a slope of 3/4
What is the equation of a line that passes through the point (0, -3) and is perpendicular to a line with a slope of 4?
One question at a time. You want to put into the equation of a line form, which is y = mx+b. You are given x and y (3, -1) and slope (m) = 3/4. Just substitute these values into the equation to solve for b. Do this now. Once you solve for b, you can put everything together.
sorry that was the wrong question What is the equation of a line that passes through the point (0, -3) and is perpendicular to a line with a slope of 4?
Doesn't matter, it's the same process.
@iambatman, the slope of the equation of the line is different from the slope of the perpendicular line.
-3=4(-1)+b
Right, just take the negative reciprocal for the slope.
y=1/4+3
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