Given the function f(x) = x3 + x2 − 2x + 1, what is the resulting function when f(x) is shifted to the left 1 unit?

f(x − 1) = x3 − 2x2 − x + 3

f(x + 1) = x3 + 4x2 + 3x + 1

f(x) − 1 = x3 + x2 − 2x

f(x) + 1 = x3 + x2 − 2x + 2

Question

Given the function f(x) = x3 + x2 − 2x + 1, what is the resulting function when f(x) is shifted to the left 1 unit?

 f(x − 1) = x3 − 2x2 − x + 3

 f(x + 1) = x3 + 4x2 + 3x + 1

 f(x) − 1 = x3 + x2 − 2x

 f(x) + 1 = x3 + x2 − 2x + 2

zzr0ck3r · Answer

f(x+1) shifts f(x) the left 1 unit

zzr0ck3r · Answer

so its $f(x+1)=(x+1)^3+(x+1)^2-2(x+1)+1$

now simplify

zzr0ck3r · Answer

if you think about what the constant term will be, you can solve without foiling....

jenniferjuice · Answer

x^3+x^2-2x+1 ?

zzr0ck3r · Answer

yes

zzr0ck3r · Answer

hmm, I only said that because it has a 1 at the end, but when I let wolfram foil I get something different

zzr0ck3r · Answer

http://www.wolframalpha.com/input/?i=expand+%28x%2B1%29^3%2B%28x%2B1%29^2-2%28x%2B1%29%2B1

zzr0ck3r · Answer

lol wait this x^3+x^2-2x+1 ?  was not an option

zzr0ck3r · Answer

its the one with a 1 at the end

jenniferjuice · Answer

okay thank u for your help :D

zzr0ck3r · Answer

npz