Question

What is the equation of a line that passes through the point (6,3) and is perpendicular to a line with a slope -3/2

Answer 1

The general form of the equation of a line is y = mx + b correct?

Answer 2

i dont know thats why i am asking for help

Answer 3

i would say yes

Answer 4

the reciprocal is the slope but what is b

Answer 5

And you would be correct.

The slope of the equation of the line is m = 2/3, right?

Answer 6

yes

Answer 7

So we can input m = 2/3 into the equation of the line as follows:

y = (2/3)x + b

Also, we are given a point on the line. (x,y) = (6,3) correct?

Answer 8

so what is B ......i think im just slow or i have bad communication...........how do i find b what is it.

Answer 9

put x y value in to the equation

Answer 10

3 = (2/3)(6) + b
3 = 2(2) + b
3 = 4 + b

Answer 11

Finish solving for b

Answer 12

what does that mean ..........it says it can only be -1 or 3 so
y=2/3x-1
or y=2/3x+3

Answer 13

HOW

Answer 14

3 - 4 = b
-1 = b

Answer 15

WHERE ARE YOU GETTIN 3-4

Answer 16

You have to plug in the values then solve for b algebraically.

Answer 17

y = mx + b <-You start with this
3 = (2/3)(6) + b <-After plugging in the known values you get this
3 = 2(2) + b <-After simplification you get this
3 = 4 + b
3 - 4 = b <-You get this after isolating b (subtracting 4 from both sides)
-1 = b <-This is the result