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OpenStudy (anonymous):
How do I graph the equation |x|-|y|=1?
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OpenStudy (anonymous):
the absolute values are always gonna be v shaped
OpenStudy (anonymous):
what do i do about |y|?
OpenStudy (anonymous):
well if i was doing this problem i use graphing tech. geogabra.org best in the biz
OpenStudy (zzr0ck3r):
I think its a diamond
OpenStudy (anonymous):
i cant use graph tech.
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OpenStudy (anonymous):
no, its not a diamond. |dw:1404344481038:dw| its sumthing like tht
OpenStudy (anonymous):
how would i draw it by hand?
OpenStudy (anonymous):
like, i dont understand how to draw the equation of the graph by hand. I'm not even sure how to start.
OpenStudy (zzr0ck3r):
notice that the point (1.5,.5) is in the graph, because 1.5-.5=1
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OpenStudy (zzr0ck3r):
so is (2,1)
OpenStudy (zzr0ck3r):
(-2,-1)
OpenStudy (anonymous):
ok.. and then?
OpenStudy (anonymous):
is there any other algebraic way to do it other than plugging in numbers?
myininaya (myininaya):
ok so you have |y|=|x|-1 right?
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myininaya (myininaya):
if y>0 then |y|=?
myininaya (myininaya):
and
if y<=0 then |y|=?
myininaya (myininaya):
recall the definition of absolute value
|f|=f if f>=0
|f|=-f if f<0
use that here for my question
myininaya (myininaya):
we can split this into two easy to graph functions
myininaya (myininaya):
now together of course it isn't a function
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