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4x+8/2x + X-1/3x = PLEASE HELP!! PLEASE.
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In 8/2x is x in the denominator?
I know this is simple but for some reason im stuck. :/
no its 4x+8 -------over 2x
You should use parenthesis to group things together. Is it (4x+8) / (2x) + (x-1) / (3x) ?
yes
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Sorry ill do that next time. Its smart..
\[\frac{4x+8}{2x} + \frac{x-1}{3x} = \frac{2(2x+4)}{2x} + \frac{x-1}{3x} = \frac{2x+4}{x} + \frac{x-1}{3x} \]
The least common denominator is 3x. \[\frac{2x+4}{x} + \frac{x-1}{3x} = \frac{6x+12}{3x} + \frac{x-1}{3x} = \frac{7x+11}{3x}\]
So then the final anser would be (7x+11)/(3x). Thats the simplest form, right?
Yes.
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Okay thank you so much. You really helped me out. :)
You are welcome.
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