Question

Find the exact value of the trigonometric function. csc(-630 degrees)

Answer 1

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Answer 2

Csc(-630°) = -csc(630°)= -csc(2*360°+90°)

Answer 3

=-csc(90°)=-1

Answer 4

Got it ?

Answer 5

thankss :D

Answer 6

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Answer 7

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Answer 8

can you answer this too cos 210

Answer 9

\(\bf Steps\)
1 - If the angle x is negative, we first use a formula for negative angles such as sin (- x) = - sin (x), cos (- x) = cos (x) and so on.

2 - Next we locate the terminal side of the angle in question, directly or using a positive coterminal angle t, which gives the sign of the trigonometric function.

3 - We find the reference angle Tr to the angle in question and use that fact that f(x) = + or - f(Tr). The sign + or - is determined using the quadrant found in step 2. If the angle in question or its coterminal angle are in quadrant 1, this last step is not needed.

Answer 10

Or you could see your Unit Circle and search where Cosine is 210.

Answer 11

oh anyway in what quadrant is csc -630 ?

Answer 12

first quadrant

Answer 13

its 2*360 + 90

Answer 14

it its in the quadrant 1 . why is the answer is negative ?

Answer 15

if
its in the quadrant 1 . why is the answer is negative ?

Answer 16

because the question has -630°

Answer 17

csc(-630°)=-csc(630°) by negative angle theorem (point 1)

Answer 18

csc(630°) will be equal to 1, then we will put -ve sign on it.

Answer 19

getting it ?

Answer 20

ah okay. can you give me a tips of solving the exact value because we have a test tommorow about that

Answer 21

ohkay i'll show u how to find cos 210°

Answer 22

cos 210° = cos (270°-60°)....agree ?

Answer 23

ohkay leave this..i'll start a new post and explain how to find values.

Answer 24

oh i used method is 210-180

Answer 25

okay i wait