Question

....need help for this two problems of differentiation of algebraic functions.
1. y= -3/4x-x^2
2. y =1/4 (2x-3)^-10 please help me solve thisss

Answer 1

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Answer 2

plwease help me solve

Answer 3

@matricked

Answer 4

@cody_123

Answer 5

\[1.y=\frac{ -3x }{ 4 }-x^2\]

Answer 6

is this the question

Answer 7

yes that is

Answer 8

\[\frac{ dy }{ dx }=\frac{ -3 }{ 4 }-2x\]

Answer 9

that the first should i do? what rule will use on that?

Answer 10

just that d/dx x^n=nx^(n-1)

Answer 11

ah. okaythe exponent rule? what next in that

Answer 12

yes

Answer 13

ah okay what next should i do

Answer 14

\[\frac{ 1 }{ 4(2x-3)^{10} }\]

Answer 15

is this is the question?

Answer 16

yes. does the other one is already done?

Answer 17

wait. the (2x-3)^-10is multiply by both of the fraction

Answer 18

\[\frac{ 1 }{ 4 }*(2x-3)^{-10}\]

Answer 19

is this question?

Answer 20

yes that is

Answer 21

\[\frac{ 1 }{ 4 }\frac{ d }{ dx }(2x-3)^{-10}\]
\[\frac{ 1 }{ 4 }*(-10)*(2x-3)^{-11}\frac{ d }{ dx }(2x-3)\]

Answer 22

\[\frac{ 1 }{ 4 }*(-10)*(2x-3)^{-11}*(2)\]

Answer 23

i will simply substitute?

Answer 24

what substitute?

Answer 25

the whole number or its the final answer

Answer 26

it is the final answer

Answer 27

ah okay thankyou so much for helping me. god bless you

Answer 28

thanks