the equation of line CD is y=3x-3. write an equation ofa line perpendicular to line CD in slope-intercept form that conatins point (3,1).
a) y=3x+0
b) y=-3x-8
c) y=-1/3x+2
d) y=1/3x +0
medal and fan will be given
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OpenStudy (anonymous):
@ganeshie8 hi can you help
OpenStudy (anonymous):
@paki hey can you help me
OpenStudy (anonymous):
@zepdrix hi can you help me please
OpenStudy (anonymous):
ok so your like is currently in slope-intercept form (y=mx+b) m=slope so the slope of your original line would be what?
OpenStudy (anonymous):
isnt the slope 3
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OpenStudy (anonymous):
yes perfect
OpenStudy (anonymous):
so 3 can also be written as positive \[\dfrac{3}{1}\]
OpenStudy (anonymous):
to find the slope of a perpendicular line, all you need to do is flip those and change the sign so it becomes negative \[\dfrac{1}{3}\]
OpenStudy (anonymous):
so would it be -1/3x+2
OpenStudy (anonymous):
from there, you can put in your two points into point slope form \[y-y _{1}=m(x-x _{1})\]
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