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find the product write your answer in exponential form 7^-7*7^-3
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\[7^{-7}*7^{-3}\]
Rule of exponents tells us to `add` the exponent values, yes? \[\Large\rm 7^{-7}\cdot 7^{-3}=7^{-7+(-3)}\]
\[8=8^{4}*blank\]
\(8 \) is the same as \(8^1\) so, \(8^1=8^4*x\). We can think of having something like \(8^1 = 8^4 * 8^{\text{blank}}\) Think of which number, when added to 4, will 1
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will give 1*
\[9^{2}*9^{-6}\]
add the exponents together
ok
\[4^{4}*blank4^{^{4}}\]
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