the x-intercept of a line is (-2 1/2,0) and the y-intercept is (0,5) what is the equation of the line in slope-intercept form?
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OpenStudy (campbell_st):
well find the slope of the line
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the general form is
y = mx + b m = slope of the line
b = y-intercept (which you are given, y = 5)
just substitute the values
OpenStudy (anonymous):
i dont get where 5 goes ? into y=mx+b?
OpenStudy (campbell_st):
that is b
OpenStudy (campbell_st):
so the equation is
y = mx + 5
that's given... you just need to slope
OpenStudy (anonymous):
y=mx+5?
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OpenStudy (campbell_st):
thats the basic equation go to the diagram and calculate the slope...
OpenStudy (anonymous):
i just dont get it
OpenStudy (anonymous):
y=2x+5?
OpenStudy (campbell_st):
yep... that's it
the rise = 5, run = 2.5 slope m = 5/2.5 or m = 2
so the equation is
y = 2x + 5
the value of b, the y-intercept, is where the line cuts the vertical axis