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OpenStudy (anonymous):
WILL AWARD MEDAL AND FAN! Can someone please explain step by step how to solve this? This is using double and half angle identities.
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OpenStudy (anonymous):
OpenStudy (jdoe0001):
well... so you're in quadrant I sine and cosine, that is, x and y, are both positive recall \(\bf sin(\theta)=\cfrac{5}{13}\to \cfrac{opposite}{hypotenuse}\to \cfrac{b}{c}\to \cfrac{b=5}{c=13}\) thus |dw:1404423477115:dw|
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