Question

ALGERBA 2 HELP PLZZZZZZZZZZZZZ FAN AND MEDAL!!!!!

Answer 1

1st point: ___6___
2nd point:___-2___
3rd point: ___-7___

Using the points above as zeros, construct the polynomial function, f(x), that will be the path of your roller coaster. Show all of your work

Answer 2

2Using both fundamental Theorem and Descartes` rule of signs, prove to the construction foreman that your funtion matches your graph. Use complete sentences.


Solve for the y–intercept for your function, f(x), and then construct a rough graph of your roller coaster. If your y–intercept is off the graph, give the coordinates of the y–intercep

Answer 3

First, think of "the foundation" as being the x-axis. In other wordsd, the roller coaster touches the x- axis at -7, at -2 and at 6, but does not go beneath the x-axis.

Thus, you automatically have three on the curve formed by the roller coaster.

Are you aware that a root of 6 corresponds to the factor (6,0) of the polynomial in question?

What are the other two factors, following this pattern?

You can obtain the polynomial in question by multiplying out the three factors mentioned. Try this, and then get back here to request some feedback. Good luck!!

Answer 4

what?? im so lost lol

Answer 5

look
you have these 3 points that the rail touch but dont go beneath them

Answer 6

yes

Answer 7

i have (6,0) and (-2,0) and (-7,0) what do i do

Answer 8

great, now we need factors , right ?

Answer 9

yeah

Answer 10

we search about the roots, to make the factors, which will allow us to make our polynomial

Answer 11

so i would get x^2-4x-12??

Answer 12

you just multiply right

Answer 13

that equation involves only 2 factors
we need 3 factors

Answer 14

right

Answer 15

so what do i do

Answer 16

we search for the third factor
which is (x+7)

Answer 17

ok

Answer 18

so we multiply them to get our function

Answer 19

x^3+x^2-28x-12x-84??

Answer 20

you there??

Answer 21

okay,
now we do the approval by both fundamental Theorem and Descartes` rule of signs

Answer 22

whats that?? lol

Answer 23

u dont know how to prove ?

Answer 24

no thats why i need help im so lost with this

Answer 25

well this kind of theorms are rarely used, i mean they used in a specific fields, i dont know actually what they are but i think you should see your books or any other resource to make it more clear to you,
and sorry for not helping you in the most important part o the question
but i assure you that our previous work was right, cause making a polynomial equation is the same through all of the fields,
and im sorry again

Answer 26

thx wb the 3rd part

Answer 27

yes

Answer 28

how do i do it lol

Answer 29

i think the third part is simply a graph to the function we made
but you have to find the y-interception points

Answer 30

how lol

Answer 31

first of all, what does y-interception points means ?

Answer 32

the points on the vertical axis

Answer 33

right, so when the point is found on the vertical axis, its x-coordination will be ..?

Answer 34

i dont understand youre ??

Answer 35

look lets leave our question for a minute,
which one of these points is on the vertical axis :
P1(2,0) . P2(0,4) . P3(1,2) ?

Answer 36

2

Answer 37

wait 1

Answer 38

why do you chose 1?

Answer 39

idk i dont remember isnt it rise over run

Answer 40

that is the slope

Answer 41

oh yeah so its 2

Answer 42

why do you chose 2?

Answer 43

cause you move to the right 0 and up 4

Answer 44

in other words, its x-coordinate is zero and its y-coordinate is 4
so the y-interception points have an x-coordinate equals to ZERO

Answer 45

yeah

Answer 46

so just plug x=0 to your polynomial to find it

Answer 47

so -84??

Answer 48

right

Answer 49

do you have a graphing program ?

Answer 50

now what

Answer 51

do you have a graphing program ?

Answer 52

no and i cant use wolphram alpha

Answer 53

you cant ?

Answer 54

no

Answer 55

why ?

Answer 56

http://www.wolframalpha.com/input/?i=y%3Dx%5E3%2Bx%5E2-28x-12x-84

Answer 57

im taking algebra 2 online and were not suppose to i got in trouble last time i used it to graph

Answer 58

but you are now kindda online !

Answer 59

?? que

Answer 60

i used it well see what happens lol

Answer 61

lol so now for 2

Answer 62

1 sec

Answer 63

you have skype right ?

Answer 64

yeah hold on thouhg lol

Answer 65

hold im im talking to someone lol its important

Answer 66

http://learn.flvs.net/webdav/educator_algebraII_v13/module04/images/04_05_assessment/04_05_assessment.jpg

Answer 67

the link does not work.

Answer 68

listen. i am sorry, but here it is very late and i have to work tomorrow.

good luck.