The length of a particular rectangle is 4 greater than the width of the rectangle. If the perimeter of the rectangle is 16, what is the area of the rectangle?

2
6
8
12
16

Question

The length of a particular rectangle is 4 greater than the width of the rectangle. If the perimeter of the rectangle is 16, what is the area of the rectangle?
 


2 
6 
8 
12 
16

sheraz12345 · Answer

Is this 4 times greater?

imstuck · Answer

Here's your drawing for this, using the perimeter formula:

imstuck · Answer

|dw:1404495803073:dw|

imstuck · Answer

If the length is 4 greater than the width, then it looks like this:

imstuck · Answer

|dw:1404495849252:dw|

imstuck · Answer

So fitting that into your formula, knowing that the perimeter measurement is 16, you get this:

imstuck · Answer

16 = 2W + 2(4+W)
16 = 2W + 8 + 2W
16 = 4W + 8
16 - 8 = 4W
8 = 4W
2 = W

imstuck · Answer

So the width is 2 and the length is 4 + 2 = 6.  The area formula for a rectangle is L * W, so 2 * 6 = 12

imstuck · Answer

the fourth choice down is what you want.

imstuck · Answer

See that?