How do you represent the (decimal) integer 50 in, oh, "hexadecimal," otherwise known as base-16? Recall that decimal is simply base-10, and binary is simply base-2. Infer from those base systems how to represent this one!

Question

anonymous · Answer

http://www.binaryhexconverter.com/decimal-to-hex-converter

hari5719 · Answer

google it

mathmate · Answer

1. Divide by 16, and the first remainder is the right-most digit in hex.
2. If the quotient is greater than 16, then divide the quotient to get he remainder as the next digit (to the left).
Repeat 2 until the quotient is less than 16.  The last quotient is the left-most digit.

Example: Convert $1728_{10}$ to hexadecimal
$$1728\div16=108 \ R\color{red}0$$
$$108\div16=\color{blue}6 \ R\color{green}{12}$$
Since $\color{green}{12}$ is written in hex as $\color{green}C$, we have the result as $\color{blue}6\color{green}C\color{red}0$.