Question

What does the graph of f(x) = 3x^2 – 2x + 1 look like?

A. a parabola that opens upward

B. a parabola that opens downward

C. a v-shaped graph that opens upward

D. a v-shaped graph that opens downward
@Cosmichaotic @mrdoldum

Answer 1

A. a parabola that opens upward

Answer 2

f(x) = 3x^2 – 2x + 1
or
y =3(x^2 -2x/3)+1
y =3(x^2 -2x/3 +1/9 -1/9)+1
y =3(x^2 -2x/3 +1/9 )-1/9+1
y= 3*(x-1/3)^2 +8/9
y-8/9=4*3/4*(x-1/3)^2
which is of the form
Y= 4(3/4)X^2 where Y= y-8/9 and x-1/3=X

Answer 3

sign of x^2 is +ve so the graph is upward opening
and it is a quadratic function
always parabola..
so its upward opening parabola

Answer 4

Thank you both :)