Simplify 3a^2b^3c^5 __________________ 8x^4y^3z
I can help you...this is quite simple once you get the hang of it, ok?
ok thanks!
Wait, you have a, b, and c in the numerator and x, y, and z in the denominator. Nothing there simplfies at all.
oh sorry it says rewrite the expression
You can only cancel between variables when the variables are the same. If you had a, b, c on top and bottom, then you could cancel.
it can't have a denominator
What do you mean by rewrite it?
so there is no denominnator or fraction line if you will
There is no way you can simply eliminate the denominator when there is no other "side" to this. If this was one expression = to another, then you could possibly do something about cross multiplying or something. Not to belittle you so please don't take this wrong, but are you sure you copied the problem correctly? And that the instructions are correct as well?
Complete this item. (Enter letter variables in alphabetical order.) Rewrite the expression so that it has no denominator. (Note: do not use a fraction line in your answer. Also, use '' for multiplication between numbers. )
3a^2b^3c^5 Over ______________ 8x^4y^3z
By any chance are you working with exponents and their negatives and the like?
yeah ^ is an exponent sign
Are you learning how to eliminate negative exponents and then how to write an expression using negative exponents? I'm trying to get at whether or not you are using negative exponents. "negative" being the important word.
Rewriting that with no denominator will cause us to have to use negative exponents.
yeah negative exponents
Very good! Ok then...
thanks!
When you move a number or a variable to the top from the bottom, you have to include a negative exponent with it. Like moving the 8 from the denominator to the numerator moves up as\[8^{-1}\] \[8^{-1}=\frac{ 1 }{ 8 }\]
By the same method, \[x ^{4}\]moves up to the numerator as \[x ^{-4}\]because\[x ^{-4}=\frac{ 1 }{ x ^{4} }\]
Are you getting the pattern here? You want to try the y^3?
umm
so it is 1/3z?
for 3 it equals 1/3
IM stuck?
Ok, let me start you off here...
Like this...I will do the first two terms from the denominator so you can see. Okk?
\[3a ^{2}b ^{3}c ^{5}8^{-1}x ^{-4}...\]Do you see how you will bring up the y^3 and the z^1?
yeah
so 3^-1
y^-3 x
It would be y^-3, no x.
what about the x then -x?
Now you have\[3a ^{2}b ^{3}c ^{5}8^{-1}x ^{-4}y ^{-3}...\]The x is to the negative 4. See it there after the 8^-1?
What about the z?
\[z=z ^{1}\]
yeah thats what im meant the z not the x. thanks!
What happens to the exponent of 1 when you bring it to the top?
it turns negative?
\[3a ^{2}b ^{3}c ^{5}8^{-1}x ^{-4}y ^{-3}z ^{-1}\]
wow great!
Yep! It does turn negative! Very good! Do you get it now?
yeah! thanks so much!
I appreciate the help!
You're so very welcome!!! (I'm a teacher...I love to help!) ; )
well your great at ti!
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